Java按位与与==和+的优先级比较-创新互联

文章目录

• • &与==
  • • 1.代码篇
    • 2.报错提醒
    • 3.改错方式
  • 2.&与=

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import java.util.Scanner;

public class NumberOne {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);

		System.out.print("Please enter a number >");
		while (scanner.hasNextInt()) {	int a = scanner.nextInt();

			System.out.println(countOne(a));
			System.out.print("Please enter a number >");			
		}
	}
	public static int countOne (int number) {int b = 1, counter = 0;

			while (number != 0) {		if (number & b == 1){		
					counter++;
				}

				number = number >>>1;
			}

		return counter;
	}
}

2.报错提醒

原因是编译器先进行b==1的返回值计算在进行按位与。

3.改错方式

import java.util.Scanner;

public class NumberOne {public static void main(String[] args) {Scanner scanner = new Scanner(System.in);

		System.out.print("Please enter a number >");
		while (scanner.hasNextInt()) {	int a = scanner.nextInt();

			System.out.println(countOne(a));
			System.out.print("Please enter a number >");			
		}
	}
	public static int countOne (int number) {int b = 1, counter = 0;

			while (number != 0) {		if ((number & b) == 1){		
					counter++;
				}

				number = number >>>1;
			}

		return counter;
	}
}

加上括号就可以啦！

2.&与=

import java.util.Scanner;

public class OddEvenBitBinary {public static void main(String[] args) {		Scanner sc = new Scanner(System.in);

		System.out.print("Please enter an integer >");
		while(sc.hasNextInt()) {	int number = sc.nextInt();
			oddEven(number);
			System.out.println();
			System.out.print("Please enter an integer >");
		}
	}

	public static void oddEven(int num) {System.out.print("The odd bit of " + num + ">");

		int j = 1;
		int i = 0;
		for (i = 30; i >= 0; i = i - 2) {	System.out.print(" " + ((num >>i) & j));
		}

		System.out.println();

		System.out.print("The even bit of " + num + ">");

		for (i = 29; i >= 1; i -= 2) {	System.out.print(" " + ((num >>i) & j));
		}
	}
}

System.out.print(" " + ((num >>i) & j)); 这一行代码的括号必须全加上，不然会出现报错！

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